specific heat of ice is 2.06 kJ/kgC. The energy stored in the water tank can be calculated as. That is a 1 ATM. 1 kilowatt hour (kWh) = 3.6 megajoules 1 megawatt hour (MWh) = 3.6 gigajoules 1 kJ = 0.278 Wh 1 MJ = 0.278 kWh 1 GJ = 278 kWh 1 TJ = 278 MWh 1 PJ = 278 GWh 1 kWh = 3.60 MJ 1 calorie (c) = 4.19002 Joules Note 1 calorie is (approximately) the amount of heat required to raise the temperature of one ml of water by 1 degree Celsius. This is the typical heat capacity of water. But I have an idea. For practical purposes, it should be precise enough. This means that you will have to pay 23 €ct to heat the bathwater with electricity and and 12 €ct to heath with gas if you take a bath (exlusive watercosts). This is the typical heat capacity of water. To heat 1 ml of water takes 4.18 Joules per degree C, the specific heat capacity. And for testing/sampling the cool-down, measure a larger drop in temperature, such as 10f, else the result will be unreliable (reading 1f or 2f changes off a small thermometer may be very inaccurate). Change ), heating elements, immersion heaters, and more, Watt density and its importance for brewery immersion heaters. One kWh is 3413 Btu’s. Hi Larry, the energy that is used to heat water from 40 degrees to 60 is the same amount that is lost when the water cools down from 60 to 40 (only changed sign). Water is heated to 90oC. One question which comes up time and again is “How many kW do I need to heat up my tank?”. Thermal radiation losses occur from direct sunlight, high water temperature or high relative humidity. The cost of electricity is for example 7.15 €ct per kWh and for natural gas is 28 €ct per m 3 of gas. It takes 667 92.7% = 720 Btu’s to heat a gallon of water using electricity. 1 BTU is the amount of heat required to raise the temperature of 1 pound of water 1 degree F. (1 kg x 1 degree C would be 3.96 BTU.) I just recently learned about hybrid heat pump water heaters for the home that have much higher heating efficiency than standard electric. Where C p is the heat capacity of water (1 BTU/lb/F) and m is the mass of the water (Assume 1 gal has 8.3 lb of water and the 3,412 BTU = 1 kWh) Solution: Energy required for heating the water to 120°F: = m × C p × ΔT = 100 gal day × 8.3 lb gal ︸ m × 1 BTU lb °F ︸ C p × (120 − 65) °F ︸ ΔT = 100 gal day × 8.3 lb gal × 1 … ( Log Out /  The surrounding temperature (where the energy can be transferred to) is 20oC. All help is greatly appreciated - where possible, assume 'normal' conditions, i.e., use a standard or generally accepted density for air. As 1 litre of water needs about 1.16 watts to raise it through 1°C in an hour, a 120 litre tank of cold mains water needs a total energy input of about 7800 watts-hours (120*1.16*56) to raise its temperature to the required level. So we've got 0.166 kWh to heat a gallon of water, or 0.166 x 40 = 6.63 kWh to heat a 40-gallon tank. This is the best set of calculators on the internet . Cost To Heat Water Using Electricity A typical electric water heater is 90.4 to 95% efficient or 92.7% average efficiency. What formula did you use to calculate the water heating power? How much depends on the shape of your pool, the quality of the insulation of the pool, the difference of the desired water temperature to the environment and how long you are willing to wait until it is heated. … (U.C. Also, the calculator is only correct in the theoretical case that while the water is being heated, no heat escapes from the water to the environment (air or walls etc.). meaning that the water would be heated in 1 hour by 3.5kW of applied heat. is more important for efficiency. 1 L water = 0.998 kg. , As another calculator for us math dummies could be total kw x cost of electrical supply. 1 Watt = 1 Joule of energy per second 1 kW = 1000 Joules of energy per second. Click HERE for our online water heat up time calculation page. That means that for every 10 litres of hot water you use will only cost you 7 cents. 1 to heath one liter of water it will cost one kcal, what equals 4.18 kJ. Labels: energy savings, math. I want to convert this to Watthours but I'm not sure how....does bringing time into the equation determine how much energy I need to expend? I'm heating a liter of water from 25C to 60C. If you have problems with the units, feel free to use our temperature conversion or weight conversion calculators. I'm under the impression that a Calorie (kcal) heats one liter of water by one degree, and so heating one liter by 35 degrees requires 35 Calories. It makes 1 out of 1.6, excellent piece of kit. 1758120 kilojoule/hour = 488.36666667 kilowatt hour One therm is 100,000 btu's. Formula to calculate electricity or gas consumption of water heating . density of water is 1g/cu.cm or 1kg/cu.d. This unit is less used than it was. The specific heat of water is 4186 Joules/kg-C. The higher element usually is for when you need to heat some water in middle of day. 1 litre for 1 degree in 1hour is 1,16 kW/h. But when the state of water changes from solid to fluid (e.g. The gas needed depends on your boiler, it's perhaps 60% efficient. Think of power as the rate at which energy is used. According to "latent heat of vaporization of water" it would take around 0.62 kWh/liter but I'm not sure...please help! Heating a full 184 litre (40g) tank costs $1.33 and $2.01 for a 279 litre (60g) tank. To boil ALL the water: natural gas, or kilowatt hours or electricity (kWh). There are many other factors including the temperature of the cold water entering the heater system, the temperature of the hot water coming out of the heater and hot taps and the cost per kWh of the energy. How do I calculate btu size for heating a swimming pool? For less than the price of a new heater tank, I now have free hot water. It depends how much you want to heat the water up by: As a general rule, the energy (in joules) to heat water is given by: Energy = mass of water (kg) x temperature rise (celsius) x 4200. There is 3.785 liters per US Gallon so these figures are 129.45 MJ of heat energy per US Gallon which is equal to 35.96 kWh of heat energy per US Gallon. Thanks!!! heat of fusion of ice is 334 kJ/kg. Hot water immersion heater elements are usually rated at 3 or 6 Kilowatts (kW). Thus,mass of 1l water=1kg. or = 488 .36 KW Time period available to heat the water (minutes), Water Heating Calculator for Time, Energy, and Power. And 1 calorie equals 4,184 Joule. The increase in temperature is 45 Kelvin (60-15) So the energy needed is 180,000 x 45 x 4.2 = 34MJ. I have done the calculation again manually in an Excel spreadsheet and got the same result. 180 litres of water is near enough 180kg. Cost of 1 litre of hot water according to appliance type . Cost To Heat Water Using Electricity A typical electric water heater is 90.4 to 95% efficient or 92.7% average efficiency. A typical electric water heater is 90.4 to 95% efficient. With a 3 hour design reheat time, this means a power input of about 2600 watts. Boil or evaporate? So 78 C rise requires 326,508 Joules per kg. I’m curious, though. The mass of the one liter of H2 produced by a typical "HHO" scam device in one minute: .000089 kg = .089 grams = 89 milligrams. I entered 688 litres start temperature 29 C end temp 37 C with 1600 watts of power. A BTU is the amount of energy required to heat 1 pound of water by 1°F (specifically from 39° to 40°F). for example 100 litres of water, to be heated from 20 ºC to 50 ºC, giving a temperature rise of 30 ºC would give – 100 x 4 x 30 / 3412 = 3.52 meaning that the water would be heated in 1 hour by 3.5kW of applied heat. So one Btu is 0.00001 therms. And this is 488.36 Kilo Watts of power (since 1J/s = 1W) The higher element usually is for when you need to heat some water in middle of day. It also should be noted that the difference between the starting temperature and the desired final application temperature is commonly referred to as delta T (ΔT). The calculators use the specific heat capacity of water of 4186 J/kg/°C (Joules per kilogram per degree Celsius). Hot water cylinders/tanks come in many shapes, sizes and capacities, ranging from 40 to over 400+ litres in larger homes. One Btu is 0.000293 kWh. Heating oil provides 138,500 British thermal units (BTU) per US gallon; 1 BTU = 0.000293 kWh; 1 US gallon = 3.78541178 litres (138,500 * 0.000293)kWh in 3.78541178 litres (138,500 * 0.000293)/3.78541178 kWh/litre = 10.720233982047786621512547837002 A 60 watt light bulb uses 60 watt-hours of energy in one hour. I have done the calculations in the calculator above for heating 33’000 US gallons from 68F to 90F in 5h (300min) and got a result of approximately 1’200’000 btuh. 3412 BTU = 1 kWh. When using a simple coil submerged in water, then it will start to heat the water just around it. The following formula is used to calculate the power of heating element needed to heat a specific volume of water by a given temperature rise in 1 hour. Hi “New pool, cold water !” The volume in gallons (5), ambient temperature (46F) and target temperature (161) are variables that will change. At $0.11/kWh, it costs 6.63 x $0.11 = $0.73 to heat a 40-gallon tank." Please remember, that the calculators above assume 100% conversion efficiency. As such, for every litre of hot water, you need to factor in: the price of a litre of water; the write-off of the purchase price and the installation cost of your domestic hot water generating system; your energy consumption to heat this litre of water. Fill in your details below or click an icon to log in: You are commenting using your WordPress.com account. Running a bath will use approximately 60 - 80 litres of water. 1 to heath one liter of water … They are also measured by heat content. There's a great answer about heating water with electricity, where anyone can easily get an idea how much would it cost to heat water just by applying one's price for kWh. Heating a gallon of water by 1°F with no losses thus takes 8.33 lbs x 1 Btu/lb = 8.33 Btu's. For rocket science one might want to calcualte it more accurately. 1000 watts is 1000 Joules per second, but spread over 1000 ml. Heating water to have a bath can be a major cost on your energy bills depending on how you heat the water and how much water you use. volume in litres x 4  x temperature rise in degrees centigrade / 3412, (4 being a factor and 3412 being a given constant), for example 100 litres of water, to be heated from 20ºC to 50ºC, giving a temperature rise of 30ºC would give –. The immersion stat will control temperature which will normally be well under boiling point - so 65 degrees or so, depending on what it is set at. For Heating Water in Tanks: KW = Liters x Temperature Rise (°C) 790 x Heat-up Time (hrs.) I just want to maintain the temperature. specific heat of steam is 2.1 kJ/kgK. L is the number of liters of water that is being heated and T is the difference in temperature from what you started with, listed in degrees Celsius. The calculators on this page compute how long it takes to heat water, how much energy is consumed, and how much heating power is required. Also we can use this formula as the basis of similar calculations for heating oil. One Btu is 0.000293 kWh. Improved calculators that support comma, dot, and efficiency, are available here: time, energy, and power. Thermal radiation losses are responsible for 20%-30% of heat energy loss in the swimming pool. The heat capacity Cp of water is 4.186kJ/kg-C So it takes 525 ÷ 92.7% = 566 Btu's to heat a gallon of water in an electric tank. The immersion stat will control temperature which will normally be well under boiling point - so 65 degrees or so, depending on what it is set at. That’s just an example, I have no idea how fast a tub cools down. One gallon of gasoline (petrol) is about 118,000 BTU. specific heat of water is 4.186 kJ/kgC. I am tasked to maintain a 110L aquarium at 22-24C outdoors in Texas. I’m trying to figure out what would it take to heat my pool using a heating pipe after the filtration pump. how to calculate power required to heat water. Great help to calculate water flow and energy consumption! I am assuming calculations take into account the specific heat capacity of water? Change ), You are commenting using your Twitter account. If i change the power to 1.6kw . it takes the same amount of energy to heat water from 48 degrees to 52 degrees as it takes to heat water from 58 degrees to 62. Hi John, This calculator tells you how long it takes to heat water from start to end temperature with a given heating power. This was super helpful in calculating the power needed to produce my hot water via solar photovoltaics. This is also The value of the specefic heat of water. I'm looking for the same calculation, but for gas. This is for a hot tub, I do not need to increase or decrease the temperature. Here’s a breakdown of how hot water is used in an average month. How much heat energy in joules is necessary to raise the temperature Of 7000 kg (7 M3) of water from 20 °C to 80 °C? Power = Energy / time This calculator tells how much energy will be consumed to heat the water from the start to end temperature. Density: 1000 kg / m 3 or 1 kg / litre This is a measure of the mass (weight) of a set volume of water. Running a bath will use approximately 60 - 80 litres of water. And as always, double check with some other source and my help is without any guarantee or similar. It takes about 1/10 kWh of energy to boil a litre of water and around 5kWh to heat a bath. of 1g water by 1˚C . is this calculation valid only when submerging the heating device in the water, or also when the water is circulating through a heating pipe using a pump? It very much depends on the surrounding temperature, the heat conductivity of your hot tub material, and the shape of the tub. I'm heating a liter of water from 25C to 60C. The insulation of where the heating device sits and whether any heat can escape into something other than the water (like a wall, concrete etc.) EDIT: My gas is billed in 15kg gas cylinders, but feel free to allow for liters of gas. Create a free website or blog at WordPress.com. 566 Btu's x 0.000293 kWh/Btu = 0.166 kWh. A litre of water at 25℃ needs a certain amount of calories to become steam at 100℃ ∆t=75℃ (75Kcal + 540Kcal =615Kcal) if I remember the figures. K). The calculators support Celcius/Centigrade, Fahrenheit, Watts (w), Kilowatts (Kw), Btuh, Joule, British termal unit (Btu), liter, gallon, kg, lb, cubic inch, cubic foot etc. The specific heat capacity of water is approx 4.2 J / g.K. The heat capacity is largely constant in the temperature range that the calculators work (34-210°F or 1-99°C). Solve for Thermal Power Roughly speaking, due to its density and viscosity, heavy oil will heat up in half the time of water, or if you prefer, require around half the heating power to heat up the same volume of water in the same period of time. One kilo calorie is the amount of heat needed to raise the temp. Also, you should have some extra power available, just to be sure. E = (4.2 kJ/kgoC) ( (90 oC) - (20 oC)) (1000 liter) (1 kg/liter) = 294000 kJ. As 1 litre of water needs about 1.16 watts to raise it through 1°C in an hour, a 120 litre tank of cold mains water needs a total energy input of about 7800 watts-hours (120*1.16*56) to raise its temperature to the required level. This means that you will have to pay 23 €ct to heat the bathwater with electricity and and 12 €ct to heath with gas if you take a bath (exlusive watercosts). Energy rates as of November 1, 2020. Over an hour it would be “kWh”. The power in watts is then found by: energy (joules) / time (seconds) To convert that answer to kilowatts, divide by 1000. At Process Heating Services, we have 2 types of customer. Specific heat capacity of water kcal/kgx°C 3: 1. Water at room temperature 22 C must be raised to 100 C and heat of vaporisation added to become a gas. At $1.20 /therm, it costs 11.31 x $1.20 = $13.58 to heat 1000 gallons. For an electrical heater that can be a good assumption, but not for a gas heater. Also we can use this information to extrapolate both ways. Heating water to have a bath can be a major cost on your energy bills depending on how you heat the water and how much water you use. Calculate the kilowatt-hours (kWh) required to heat the water using the following formula: Pt = (4.2 × L × T) ÷ 3600. The cost of electricity is for example 7.15 €ct per kWh and for natural gas is 28 €ct per m 3 of gas. Since water gets lighter when heated it will start to ascend around the coil and cold water will flow to the coil from below. 1 Watt = 1 Joule of energy per second 1 kW = 1000 Joules of energy per second. If you can test how fast the water cools down in your tub, then you can calculate how much heating power is required to prevent that from happening. Irvine) Heating a gallon of water by 1°F with no losses thus takes 8.33 ÷ 100,000 = 0.00008.33 therms. Calculation for working out factor to convert litres of heating oil into kWh / litre. = (294000 kWs) (1/3600 h/s) = 81.7 kWh. Also we can use this information to extrapolate both ways. 1 litre of water is 1kg 1 meter cube = 1000 Ltrs M = 7 meter cube = 7000 Ltrs or 7000 Kg The heat capacity Cp of water is 4.186kJ/kg-C ΔT = 80-20 = 60 C If you want to boil it and turn it all completely into steam, you'll need another 0.7421 kilowatt-hour 100 kcal of heat is required to raise the temp of 1 kg water from 0 ˚C to 100 ˚C. 1) thermal transfer from heat source to water 2) As the water is heating up, the loss of water temperature due to conduction to the cooler surrounding air. ( Log Out /  Hot water cylinders/tanks come in many shapes, sizes and capacities, ranging from 40 to over 400+ litres in larger homes. This calulator tells you how much minimum heating power is required to heat the water within a specified amount of time. • The heat content of one gallon of fuel oil roughly equals that of 41 kWh of electricity, 137 cubic feet of natural gas, 1.5 gallons of propane, 17.5 pounds of air-dried wood, 17 pounds of pellets, a gallon of kerosene, or 10 pounds of coal. ie, the metal kettle on the gas hob, would loose more water temperature, than say the plastic, electric kettle, as plastic is a better heat retainer than metal. Under partial vacuum, such energy requierement can be less. It would be really cool to see a calculator that takes this new technology into account. The answer is 6 hours 24 minutes. @Anna I think of it this way: the power limit of heating coil simply submerged in water is reached when the water starts to boil around the coil while the water in other places is still much colder. Water Litre to kg: 1 Litre = 0.999975 kg, so for all practical purposes 1 L = 1 kg Water kg to Litre: 1 kg = 1 litre Example: LPG Gas 14.2 kg Equals How Many Liters with 75% Butane For LPG (propane) 1 kg = 1.96 L. Therefore, 14.2 kg = 27.832 L. For LPG (butane) 1 kg = 1.724 L. Therefore, 14.2 kg = 24.48 L 1kcal=1000cal. Gas Engineer. To determine BTU lost can I use the “Water Heating Energy Calculator” only backwards? 1 meter cube = 1000 Ltrs 250 us gallons at 105f with moderate insulation… would 100 watts DC heater maintain this temperature? This is why the calculators complain in these situations. Converesely, if we only use half the heating power, 1.75kW, it will take twice as long to heat up to desired temperature, ie, 2 hours. The two keys they had were that it cost $0.51 to heat 40 gallons using gas or $0.73 using electric. At $0.30/kWh that's $2.85. annual and total lifetime water heating costs based on different water heating systems and energy sources. Appreciate the calculators but i was wondering if you could tell me the exact equations used for the “Water Heating Energy Calculator” or give some sort of excel sheet to double check it. Our updated website is up, running and ready for viewing. I am looking for how much energy is need to maintain water temperature. P = calculated heat transfer (kW) h e = evaporation energy of the steam (kJ/kg) The evaporation energy at different steam pressures can be found in the Steam Table with SI Units or in the Steam Table with Imperial Units. of 1kg water by 1˚C . If using electric it's near enough 100% energy conversion from energy paid for to heat, but leccie is more expensive than gas per kWh (see bills). One kWh is 3413 Btu's, so one Btu is 1/3413 = 0.000293 kWh. Now, 1 kWh contains 3.6 MJ/kWh. -2°C to + 2°C) or from fluid to gas (e.g. It complains when volume is 0.25 US gallon, saying volume must be greater than zero. The calculators assume 100% efficiency and no loss of energy during the heating process. watts) to water. Hi all. Start temp as final and end temp as start. If we can calculate the volume of water and the required temperaure rise, we can answer this question. We normally see energy in our electricity meter and bill as kilo-watt hours, rather than kilo-joules, so we have to divide by 3,600 (the number of seconds in an hour) to convert them — so 18,900 KiloJoules is 5.25 kilowatt-hours (18900 ÷ 3600 = 5.25) So basically I use 5.25 electricity credits every day heating up water. Problems with limit calculations: It complains if the end temp is 212°F or even 211°F, saying it must be less than boiling. I’ve been looking for a simple way to ballpark the size of a solar thermal hot water system – and this makes it dead simple! Change ), You are commenting using your Facebook account. An I missing something here? May 21, 2010 #4 PaulS1950. Volume of fluid to heat in litres: Starting temperature degrees C: Target temperature (finishing) degrees C: Heating power kW: Density of water kg/dm 3: 1. time required to reach target temperature at given power: hours There's a great answer about heating water with electricity, where anyone can easily get an idea how much would it cost to heat water just by applying one's price for kWh. It is the way it is taught at school. Using the “Water Heating Power Calculator” above (250 us gallons, start temperature 103f, end temperature 105f, 120min) tells us that a heating power of 611 watts is required. Energy E = m•Cp•ΔT = 7000 x 4.186 x 60 = 1758120 kJ Specific Heat Capacity: 4200 J / kg / C This is a measure of the amount of energy, measured in Joules, required to heat water. Lecci is about 10p / kWh, so about 50p for a bath and 10p for a litre of tea. I'm looking for the same calculation, but for gas. 1 litre of water is 1kg Thank you. How to calculate the kW required to heat a volume of water in a particular time. A simple formula to estimate the energy required to heat a volume of water is : E = C*V*DeltaT/PR Where E = energy in kWh C = Specific heat of water - 4.187 kJ/kgK, or 1,163 Wh/kg°C V = volume of water to heat deltaT = Th-Tc Th = temperature of hot water With a 3 hour design reheat time, this means a power input of about 2600 watts. Pt is the power used to heat the water, in kWh. I do not think it makes much of a difference in practice. Density: 1000 kg / m 3 or 1 kg / litre This is a measure of the mass (weight) of a set volume of water. One kWh is 3413 Btu's, so one Btu is 0.000293 kWh. It would be more complicated to build calculators that can handle that and I have not done so. Great calculator. For 4 hours 488/4 = 122kw at 1:57 PM. Wouldn’t it be faster in the latter case, because the water flow would exchange heat more efficiently than just by convection? Thanks! The calculators cannot deal with dots or comma. I am wondering though, doesn’t heat capacity increase with temperature, potentially throwing off the calculation? However this will require a much lower watt density than on a oil heater. Often, energy is measured in kWhs So, this is 12.8889 kWh/liter of heat energy. In turn the abbreviation, for one thousand, is k. Bringing these two together, a kilowatt is a “kW”, not as you have, “Kw”. There are many other factors including the temperature of the cold water entering the heater system, the temperature of the hot water coming out of the heater and hot taps and the cost per kWh of the energy. Hence, the energy needed is 34/3.6 = 9.5 kWh. Hi, I am trying to calculate the energy required to heat air that is 6.7 degrees C to 21 degrees C, in kilowatt hours, and for a range of other temperatures (5.7, 6.9, 9.5..... and many others, all to 21 degrees celsius/centigrade). However, oil needs a much lower watts density element than water, as described in the “How to choose an oil heater” article. This calculator is great. If we only have a 1kW element available, we will expect a heat up time in excess of 3 hours. The answer was 4 hours. For Heating Water in Tanks: KW = Liters x Temperature Rise (°C) 790 x Heat-up Time (hrs.) There are those who tell us what they want as they know their exact requirements. Also we can use this information to extrapolate both ways. Let’s make a calculation example for a tub with 250 us gallons that cools down from 105f to 103f in 2 hours. 1 litre of water has a mass of 1 kg. How long would it take a kettle with a 1kW heating element to heat 1 litre of water? You used 0.001163 of one kilowatt-hour to heat your liter of water from 0°C to 1°C. M = 7 meter cube = 7000 Ltrs or 7000 Kg For 8 hours 488/8 = 61kw. One kWh is 3413 Btu’s. heat of vaporization of water is 2256 kJ/kg. They are saying the modern heat pumps can give you 3.8 watts worth of hot water (or something close to that) for each watt that the heat pump uses. So if you want to raise the temperature of 1 litre of water (1 litre = 1000g for water) by 80 degrees Celcius, your calculation should look like this: 1000g*4,184J/ (g*°C)*80°C= 334 720 Joules 1 kWh = 3 600 000 Joules, because 1 watt of power during 1 second equals 1 Joule. Specific heat capacity of water kcal/kgx°C 3: 1. 1kWh = 1000W x 3600s = 3.6MJ. I’m looking at a 50,000 btu boiler with a heat exchanger to heat a 33,000 gallon pool to 90 degrees f. I’ve run then calculation through the formula above, and it’s coming up with a 600,000 btu boiler to raise the water temp (68f) in 5 hours to 90f, which seems to be a really high number? One calorie is the amount of heat needed to raise the temp. A kilocalorie (C) is the amount of energy needed to heat 1 liter (1000 milliliters or 1000 cubic centimeters) of water one degree centigrade. If you use a 611 watts heater in this example, then it will be about enough to reverse this cool-down from 105f to 103f by heating the water back up from 103f to 105f during the same period (realistically, of course, the water does not cool down, but stays at the same temperature). Last updated on April 16th, 2020. is there a formula to calculate the temperature required for 5 gallons of water that will increase the temperature of a stainless steel 15.5 gallon tank from 46F to 161F. While this appears to be a conservative estimate of water-related energy use, our findings suggest that the carbon footprint currently associated with moving, treating and heating water in the U.S. is at least 290 million To heat the same water volume in half the time (30 minutes) would need twice the heating power, ie, 7kW. So, the energy required to raise the temperature of 7000 kg of water from 20C to 80C is: I'm under the impression that a Calorie (kcal) heats one liter of water by one degree, and so heating one liter by 35 degrees requires 35 Calories. water-related energy use is at least 521 million MWh a year—equivalent to 13% of the nation’s electricity consumption. Nice calculator buttt…… you’ve got the abbreviations for the metric units incorrect. that is impossible to calculate with the information given. EDIT: My gas is billed in 15kg gas cylinders, but feel free to allow for liters of gas. Calculation for working out factor to convert litres of heating oil into kWh / litre. I am guessing its q=m*cp*dt but when I do the calcs by hand, i get something off so i would like to know my mistake, How much heat energy in joules is necessary to raise the temperature Of 7000 kg (7 M3) of water from 20 °C to 80 °C? Heating oil provides 138,500 British thermal units (BTU) per US gallon; 1 BTU = 0.000293 kWh; 1 US gallon = 3.78541178 litres (138,500 * 0.000293)kWh in 3.78541178 litres (138,500 * 0.000293)/3.78541178 kWh/litre = 10.720233982047786621512547837002 Heat capacity formula. ( Log Out /  This way a circulation develops in the water container given the shape of the water container permits it. This is great. 98°C to 102°C) this does not hold true any more. Is that realistic? To heat the same water volume in half the time (30 minutes) would need twice the heating power, ie, 7kW. Change ), You are commenting using your Google account. ( Log Out /  Thank you! Let's call that 92.7% on average. Save my name, email, and website in this browser for the next time I comment. To heat the water to boiling: E = 4.186 kJ/kgC x 0.998 kg x 76C = 317.5 kJ = 0.088 kW-hr. Often, energy is measured in kWhs Last edited: Jun 16, 2016. ΔT = 80-20 = 60 C 1 C. colshaws. Straight to the point. It takes 667 92.7% = 720 Btu’s to heat a gallon of water using electricity. Specific Heat Capacity: 4200 J / kg / C This is a measure of the amount of energy, measured in Joules, required to heat water. The calculators cannot handle points or commans, only whole numbers. Posted on March 13th, 2016 Example - Batch Heating with Steam . As for efficiency, an electrical water heater can convert electricity with almost 100% efficiency to heat that can be transferred to the water. Generally, oil heats up in half the time of water, due to its density. At $1.20 /therm, it costs 11.31 x $1.20 = $13.58 to heat 1000 gallons. meaning that the water would be heated in 1 hour by 3.5kW of applied heat. So they may complain when you input commas or points. 488 kwh for 1 hour A Watt is named after James Watt hence the abbreviation is a capital W. A thousand of something is a “kilo” for example a kilogram. This kind of thermal radiation is similar to feeling the heat of a campfire on your face from a distance. Sweet! Hot water immersion heater elements are usually rated at 3 or 6 Kilowatts (kW). Only input whole numbers, do not use a comma or point. Your calculators are a big help in figuring the size of the heat sump. I have saved the page to my home screen. For that reason, these values are the minimum and some margin should be added to them. Thats $0.01275 per gallon for gas and $0.01825 per gallon with electric. Your immersion could be slightly faulty, or be covered with scale in some hard water areas . C p is the specific heat of water (4.186 J/gm deg C) The calculator below can be used to determine the temperature delta or rise for a given cooling water application (heat load or power dissipated and cooling water flow rate) using the first formula above. As for effectiveness, a large enough pipe with a pump can probably in theory transfer more heat per second (meaning power, e.g. Volume of fluid to heat in litres: Starting temperature degrees C: Target temperature (finishing) degrees C: Heating power kW: Density of water kg/dm 3: 1. time required to reach target temperature at given power: hours If you have problems with the units, feel free to use our temperature conversion or weight conversion calculators. The amount of energy needed to raise the temperature of 1 g of water by 1 degree Celcius or (1 Kelvin) equals 1 calorie. In the United States, the most commonly used value for expressing the energy value or heat content of a fuel is the British thermal unit (Btu). I know that "both heat of vaporization plus the heat required to raise the water to 100°C" but the energy required to raise the water to 100°C contributes just 5% of the total requirement . There are others who need guidance and advice as to what they need.